Whats the distance of segment BC, if B(5,6) and C(1,3).

Answer 1

To find the distance between two points we need to subtract our points with the following formula:

d=√(x₁-x₂)²+(y₁-y₂)²

B(5,6) and C(1,3)

Let identify our parts: x₁=5 from point B, x₂=1 from point C, y₁=6 from point B, and y₂=3 from point C

Then we substitute the number in the distance formula as such:

d=√(5-1)²+(6-3)²

_d=√(4)²+(3)²

^d=√16+9

^d=√25

^{When we take square root of 25 which is perfect square}

^d=5

^{Any further questions on the concept of distance formula please let me know.}

Answer 2

When you're asked to find the distance between two points, use the distance formula:

d = sqrt[(x₁ - x₂)² + (y₁ - y₂)²]

In our case, let's say B is (x₁, y₁) and C is (x₂, y₂). So:

d = sqrt[(5 - 1)² + (6 - 3)²]

d = 5

Hope this was helpful.