Inactive Tutor answered 04/06/13
Tutor
New to Wyzant
∂f/∂x = x'x e^(xy^2) + x(e^xy^2)'x = e^xy^2+xy^2*e^(xy^2)
∂f/∂y = x(e^xy^2)'y + (cosy^2)'y = 2x^2 y (e^xy^2) - 2y sin(y^2)
∇f
= <∂f/∂x, ∂f/∂y>
= <e^xy^2+xy^2*e^(xy^2), 2x^2 y (e^xy^2) - 2y sin(y^2)>