
Bradford T. answered 06/27/24
Retired Engineer / Upper level math instructor
∫x√xet(sin(t)+t2)dt
From fundamental theorem of calculus part 1:
d/dt∫h(x)g(x) f(t)dt =f(g(x))g'(x)-f(h(x))h'(x)
Where:
g(x) = x
g'(x) = 1
h(x) = √x
h'(x) = 1/(2√x)
f(t) = xet(sin(t)+t2)
Just substitute in values into the FTC to finish

Doug C.
And here is a way to confirm the answer on Desmos: desmos.com/calculator/vgrisuvblj06/27/24