J.R. S. answered 06/06/24
To determine the efficiency of invertase, we can use the data provided, as follows:
efficiency = kcat / Km
kcat = 1x104 sec-1 (although you didn't provide the units)
Km = 25 mM = 2.5x10-2 M
efficiency = 1x104 / 2.5x10-2
efficiency = 4x105 M-1 (units are M-1 because kcat is 1st order constant and Km is 2nd order constant)
Vo = Vmax[S] / Km + [S]
First, we need to find Vmax, which is equal to kcat[E] and [E] = 20 uM as given in the question
Vmax = (1x104 sec-1)(20x10-6 mol / L)
Vmax = 0.20 mol / L-sec = 0.20 M/sec
Now, plugging this back in to the Vo equation and solving for Vo
Vo = 0.20 M/sec (0.012 M / 0.025 M + 0.012 M) = 0.20 M/sec (0.012 M/0.037 M)
Vo = 0.065 M/sec or 0.065 moles/L-sec or 65 mmoles / L-sec
Please be sure to check all of the above math as I am prone to making math errors.