Integrate with respect to y

Question

Y^1/2 =

I know the answer is 2/3y^1/2+c but what is the working out.

Thank you

Answer 1

integrate y^(1/2)

= y^(3/2)/(3/2) +C

= (2/3)y^(3/2) +C

= (2/3)y^1.5+ C

increase the power of y by 1, from 1/2 to 3/2

and divide by 3/2