Given the vertex form of f(x)= (x+1)^2-9 write the factored form

Answer 1

(x+1)^2 -9

= x^2+2x +1-9

= x^2+2x-8

= (x+4)(x-2)

or use the difference of squares formula a^2 -b^2 = (a-b)(a+b) with a=x+1, b=3

(x+1)^2 -9

= (x+1-3)(x+1+3)

=(x-2)(x+4)

Answer 2

first simplify (x+1)^2 as

(x+1)(x+1)

=x*x +x*1+1*x+1*1

=x^2 +2x +1

then subtract( 9)

x^2 +2x +1-9

=x^2 +2x -8

=(x-2)(x+4)

Answer 3

Here you go! I hope this helps :)