or A parabola opening up or down has vertex (0,0) and passes through ( – 16, – 16). Write its equation in vertex form. Simplify any fractions.

Answer 1

Plug in the given values for the vertex into the parabola vertex equation format:

y = a(x-0)² + 0 = ax²

Next, plug in the other given value:

-16 = a(-16)² = 256a

Dividing both sides by 256:

a = -1/16

So the vertex form of this parabola is:

y = -(1/16)x²

Answer 2

it's a downward opening parabola

with general form y=ax^2

plug in the point x=y=-16

-16 = a(-16)^2

a = -16/(-16)^2= -1/16

when a is negative,the parabola is downward opening

y= -x^2/16

or

y = (-1/16)x^2

the vertex = (0,0)

to be more explicitly in vertex form you might write it as

y = (-1/16)(x-0)^2 + 0

as the general form is

y = a(x-h)^2 + k where (h,k) = the vertex = (0,0) in this problem