Raymond B. answered 05/11/24
Math, microeconomics or criminal justice
P(m is e) = .95
320 m selected
P(300 m are e) = ?
300 out of 320 = 93.75%
expected e out of 320 m would be .95(320 = 304
300 is slightly less than expected
P(m is not e) = .05=q, .95=p, mean=np, standard deviation = sqr(npq)= about 3.9 = about 4
one standard deviation below the mean is greater than (1-.68)/2 = .32/2 = .16
P(at least 300 out of 320) = about .84% using the empirical rule and binomial as an approximation to the normal distribution
for more precise calculation, use z tables or a z calculator
with z = (300-304)/sqr(320(.95)(.05))= about -4/3.9