In a game, you have a 1/22 probability of winning $135 and a 21/22 probability of losing $10. What is your expected winning?

Answer 1

(1`/22)(135)- (21/22)(10)

about 6.14 - 9.55

= - $3.41

or

135 -21(10)=135-210=-$75

You expect to lose 75 in 22 tries

or75/22 in one try

= lose about $3.409090909...

= about $3.41

of course in one try you either lose 10 or win 135

and you expect to lose $10

and never expect to lose $3.41

but expected loss is a theoretical number similar to the

expect number of children in an average family = 3.4 as no family has 3.4 children

but it's the "expected" number