Mark M. answered 05/04/24
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
an = (-9)n / (2n+1)!
an+1 / an = [((-9)n+1 / (2n+3)!)) ] [(2n+1)! /(-9)n] = -9 / [(2n+3)(2n+2)]
limn→∞ l an+1 / an l = 0 < 1
By the Ratio Test, the series converges.