Raymond B. answered 05/04/24
Math, microeconomics or criminal justice
9953 at t=15 midnight
4000 at t=0
4800 at t=3
4800/4000= 1.2 = e^3r
r = (1/3)ln1.2
A = 4000e^(15(1/3)ln1.2)
= 9953.28
Natalia A.
asked 05/04/24During a research experiment, it was found that the number of bacteria in a culture grew at a rate proportional to its size. At
99:00
AM there were
4 comma 0004,000
bacteria present in the culture. At noon, the number of bacteria grew to
4 comma 8004,800.
How many bacteria will there be at midnight?
Raymond B. answered 05/04/24
Math, microeconomics or criminal justice
9953 at t=15 midnight
4000 at t=0
4800 at t=3
4800/4000= 1.2 = e^3r
r = (1/3)ln1.2
A = 4000e^(15(1/3)ln1.2)
= 9953.28
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