Raymond B. answered 05/04/24
Math, microeconomics or criminal justice
9am 4,000 time t=0
noon 4,800 time t=3
midnight ? time t=15
4800=4000e^rt
48/40 = e^3r
3r = ln1.2
r = (ln1.2)/3
at midnight t=15
A= 4000e^(15/3(ln1.2))
A= 4000e^5ln1.2
= 9953.28
Natalia A.
asked 05/04/24During a research experiment, it was found that the number of bacteria in a culture grew at a rate proportional to its size. At
99:00
AM there were
4 comma 0004,000
bacteria present in the culture. At noon, the number of bacteria grew to
4 comma 8004,800.
How many bacteria will there be at midnight?
Raymond B. answered 05/04/24
Math, microeconomics or criminal justice
9am 4,000 time t=0
noon 4,800 time t=3
midnight ? time t=15
4800=4000e^rt
48/40 = e^3r
3r = ln1.2
r = (ln1.2)/3
at midnight t=15
A= 4000e^(15/3(ln1.2))
A= 4000e^5ln1.2
= 9953.28
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