Mark M. answered 04/25/24
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
F(1) = ∫(0 to 1) sin(t3)dt Δt = (b-a)/n = (1-0)/4 = 0.25
≈ [(b-a) / (2n)] (sin0 + 2sin(0.25)3 + 2sin(0.5)3 + 2sin(0.75)3 + sin1)
= (0.125)(0 + 2sin(0.25)3 + 2sin(0.5)3 + 2sin(0.75)3 + sin1)
Evaluate. Note: Calculator must be in Radian mode.