Log help please

Question

Given that loga(3)≈0.5and loga(5)≈0.73l, evaluate each of the following. Hint: use the properties of logarithms to rewrite the given logarithm in terms of the the logarithms of 3 and 5.

a)  loga(1.8)≈

d)  loga(0.6)≈

e)  loga(75)≈

Answer 1

loga3 =.5

loga5 = .731

e) loga75 = loga(3(25)) = loga(3(5^2) = loga3 + 2loga5

= .5 + 2(.731)

= .5 + 1.462

= 1.962

d) loga.6 = loga(3(.2)) = loga(3(1/5)) = loga3 + loga1 - loga5

= .5 + 0 - .731

= -.231

a) loga1.8 = loga(9(.2) = loga9+ loga.2 = loga(3^2)-+ loga(1/5)

= 2loga3 + loga1 - loga5

= 2(.5) +0 - .731

= 1- .731

= .269