Find the following probabilities. (Round all answers to four decimal places.)

Question

(b) p( 1.20 < z < 1.87 )

(c) p( z < -1.87 )

Answer 1

P(1.2<z<1.87) = 8.4328%

P(z<-1.87)= .030742 = 3.0742 %

use z tables or a z calculator

to find areas under the normal curve

area= probability

P(z>1.2)= .11507

P(z>1.87) =.030742

P(1.2<z<1.87) = P(z>1.2)-P(z>1.87) = .11507-.030742 =.084328

=8.4328% chance

P(z<-1.87)=P(z>1.87) = .030742 = 3.0742%