Trigonometry Problem

Question

A surveyor starting from a point A moves N. 32°30′ E. a distance of 546′ 11.25″ to point B. Next, she moves N. 56°54′ E. a distance of 430′ 4.75″ to point C. Next, she walks S. 6°1′ W. a distance of 1397′ 10.75″ to point D. Finally, she returns to the starting point.

1-What distance must she walk to return to the starting point? (Answer accurate to the nearest quarter inch.)

 .... feet & .... inches

2-What heading does she walk from the fourth point to return to the starting point? (Answer accurate to the nearest minute.)

N...°.... ′ W.

What is the acreage of this plot of land?

area =  ....acre

Notes:

* the prime symbol in an angle represents minutes: 60′ = 1°

* the prime symbol in a length represents feet; double prime = inches;

* 1 acre = 4840 yd²

* 1 acre = 43,560 ft²

* an angle like N 20 E means 20 degrees east of north.

Answer 1

1. She must walk 859 feet and 10.75 inches to return to the starting point.
2. The heading from the fourth point back to the starting point is N 126° 12′ W.
3. The area of the plot of land is approximately 10.39 acres. ​​