Raymond B. answered 04/19/24
f(x)=y = 6(x-2)(x+8)(x+3)
y = 6(x-2)(x^2 +11x+24)
y = 6(x^3 +11x^2 +24x -2x^2 -22x -48)
y = 6(x^3 +9x^2 +2x -48)
y =6x^3 +54x^2 +12x -288
is the polynomial with leading coefficient 6, zeros 2, -8 and -3
f(2) = 6(8)+54(4) +12(2) -288
= 48+216+24-288 = 288-288=0
f(-8)=0= f(-3)=f(2)