
Doug C. answered 07/22/24
Math Tutor with Reputation to make difficult concepts understandable
There are 13 ranks to choose from, let's say for the 3 of a kind. (Those ranks are A,K,Q,J,10,9,8,7,6,5,4,3,2).
There are 4 cards of each rank.
(13C1)(4C3) gives the number of ways to get 3 cards of the same rank. Now we need to find the number of ways to get the pair (2 cards of a different rank.
There are 12 ranks remaining to choose from:
(12C1)(4C2), but this time we are only choosing two of the 4 from the selected rank.
The total number of full house hands:
(13C1)(4C3)(12C1)(4C2)
(13)(4)(12)(6) = ?