Hi Avneet,
If we're looking for the inverse function, that means that we're wanting to find a model that has all of the same points as its original function, except their x and y coordinates are switched!
As a result, to find the inverse function, we can do so by simply switching x and y from the original function and solving for y again!
𝑓(𝑥) = 2𝑒(2𝑥−1) − 3
y = 2𝑒(2𝑥−1) − 3
First, switch x and y.
x = 2𝑒(2y−1) − 3
Next, we can first add 3 on both sides to get:
x + 3 = 2𝑒(2y−1)
Then, we can divide by 2 on both sides and get:
x + 3 = 𝑒(2y−1)
2
After that, we can take the natural log (ln) of both sides. It would help us here because a natural log is specifically the log with a base e, Euler's number, and that will leave us with 2y - 1 on the right side!
ln((x+3)/2) = 2y - 1
Add one to both sides to get:
ln((x+3)/2) + 1 = 2y
Finally, divide by 2 on both sides to get the inverse function!
f-1(x) = ln((x+3)/2) + 1
2
If you graph both f(x) and its inverse, you should find that it is symmetric about y = x!
Any questions, let me know.
Thanks!

Doug C.
Avneet, check it out here. desmos.com/calculator/jdccsnvf7a04/18/24