F(1, 0, 0) = (3, 1, 0)
F(1, 1, 0) = (a, 1, 1)
F(0, 0, 1) = (0, 0, 1)
F(1, 1, 0) = F[1(1, 0, 0) + 1(0, 1, 0) + 0(0, 0, 1)]
F(1, 1, 0) = F(1, 0, 0) + F(0, 1, 0)
So, F(0, 1, 0) = F(1, 1, 0) - F(1, 0, 0) = (a, 1, 1) - (3, 1, 0) = (a-3, 0, 1)
The standard matrix, M , for F is the 3x3 matrix with first column F(1, 0, 0) = (3, 1, 0), second column
F(0, 1, 0) = (a-3, 0, 1) and third column F(0, 0, 1) = (0, 0, 1).
If a-3 = 0, then the second and third columns of M are the same, so there are only 2 linearly independent columns, which means that the column space is 2 dimensional. Since M is a square matrix, the row space and column space have the same dimension. So, the row space is also of dimension 2.