If a person is randomly chosen from the towns population, what is the probability that the person is under 18 or employed part-time?

Question

Use the data in the table below, which shoes the employment status of individuals in a particular town by age group.

Age Full-time Part-time Unemployed

0-17 22 165 375

18-25 380 181 171

26-34 411 68 24

35-49 529 179. 147

50+ 434 162 258

If a person is randomly chosen from the towns population, what is the probability that the person is under 18 or employed part-time?

Answer 1

I'm getting 1152/3506 ≈ 32.86% from the same number set, etc.

Answer 2

total of middle column + total of 2nd row minus 165, all divided by total of all the numbers

(22+375+ +181+ 165+68+ 179+162)/3506

=1152/3506

= about 32.858% chance a randomly selected person is under 18 or part time employed

probability of either part time or under 18

= P(<18) +P(part-time) - P(<18 & part-time)

= 562/3506 +755/3506 -165/3506= 1152/3506

so subtract out 165 because otherwise you double count it, as it shows up twice, both in the 1st row and in the 2nd column