
William W. answered 04/10/24
Top ACT Math Prep Tutor
There are 4 suits, each having:
A, 2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K (13 total cards per suit)
The face cards are J, Q, K (3 cards per suit)
So 13 cards x 4 suits = 52 total cards.
And, since there are 3 face cards in each suit, there are a total of 12 face cards (3 face cards per suit x 4 suits = 12 face cards).
So, for the first draw, the probability of getting a face card is 12/52 or 3/13.
For the second draw, since you have already drawn a face card, there are now 51 total cards left with 11 face cards making the probability of drawing a face card on the second draw 11/51.
1st draw: 3/13
2nd draw: 11/51
Total probability = (3/13)(11/51) = 33/663 or 11/221