All the middle terms cancel out, leaving y8 + 64.
You can factor as:
(y4 + 4y2 + 8) * (y4 - 4y2 + 8)
If you are allowed to use complex numbers, it can be factored more.
James S.
04/10/24
Francis G.
asked 04/10/24Using which identity or steps can I use to expand
y8 + 64
to
y8 + 4y6 + 8y4 - 4y6 - 16y4 - 32y2 + 8y4 +32y2 + 64
Is there a method I can use to find other factors?
All the middle terms cancel out, leaving y8 + 64.
You can factor as:
(y4 + 4y2 + 8) * (y4 - 4y2 + 8)
If you are allowed to use complex numbers, it can be factored more.
James S.
04/10/24
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Francis G.
Sum of two squares and sum of two cubes doesn not work. As (y2 + 4) * (y4 - 4y2 + 16) expands and simplifies to y^6 + 8y^4 + 32y^2 + 64 and not y^8 + 6404/10/24