All the middle terms cancel out, leaving y8 + 64.
You can factor as:
(y4 + 4y2 + 8) * (y4 - 4y2 + 8)
If you are allowed to use complex numbers, it can be factored more.
James S.
tutor
Have you multiplied the above factorization? It works.
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04/10/24
Francis G.
Sum of two squares and sum of two cubes doesn not work. As (y2 + 4) * (y4 - 4y2 + 16) expands and simplifies to y^6 + 8y^4 + 32y^2 + 64 and not y^8 + 6404/10/24