Inactive Tutor answered 04/08/24
Po= 2522 kg
7% per day = decay rate = .07
what is the mass after 3 days?
A=Poe^rt where e=an irrational constant =about 2.718281828...
A=2522e^.21
= about 3142.6 kg after 3 days, rounded off to one decimal place
Courtney K.
asked 04/08/24The mass of a radioactive substance follows a continuous exponential decay model. A sample of this radioactive substance has an initial mass of 2522 kg and decreases continuously at a relative rate of 7% per day. Find the mass of the sample after three days.
Do not round any intermediate computations, and round your answer to the nearest tenth.
Inactive Tutor answered 04/08/24
Po= 2522 kg
7% per day = decay rate = .07
what is the mass after 3 days?
A=Poe^rt where e=an irrational constant =about 2.718281828...
A=2522e^.21
= about 3142.6 kg after 3 days, rounded off to one decimal place
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