The length of a rectangle is three times its width. If the perimeter of the rectangle is 72 in, find its length and width.

Question

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Answer 1

Let w be the width of the rectangle. Then its length is 3w.

The perimeter P of a rectangle is twice its width plus twice its length, so,

P = 2w + 2(3w) = 72

So 2w + 6w = 8w = 72. Solving for w gives w = 9 inches.

Answer 2

L=3w

72 = 2w + 2L

36 = w+L

36= w +3w = 4w

w = 36/4 = 9 inches wide

L=3(9) = 27 inches Long

Answer 3

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