(a). W is not a subspace of R4 since the zero vector (0,0,0,0) is not in W.
(c). Find real numbers a, b, c so that a(-1,1,0,0) + b(-2,0,1,0) + c(1,0,0,1) = (4,-1,1,5)
Equating components, we have:
-a - 2b + c = 4
a + 0 + 0 = -1
0 + b + 0 = 1
0 + 0 + c = 5
So, a = -1, b = 1 and c = 5.
Mark M.
03/23/24
Zann H.
how about part b? and for part c, what does [(4, -1, 1, 5)] subscript T even mean?03/23/24