First step is to do long division and get
2 + [ (-x^2 +4x+7)/(x^3-x^2+4x-4)]
Next factor the denominator of the term on the right by noticing that x=1 is a root of x^3-x^2+4x-4, so it is divisible by (x-1). Perform long division to rewrite the denominator as (x-1)(x^2+4). Thus the integrate is now
2 + [ (-x^2 +4x+7)/((x-1)(x^2 +4))]. Next, use partial fractions to rewrite
[(-x^2 +4x+7)/((x-1)(x^2 +4)) = A/(x-1) + (Bx+C)/(x^2 + 4)
and take a common denominator on the right to get A=2, B=-3 and C=1. So now the integrand is
2 +. 2/(x-1) + (-3x+1)/(x^2 +4)
= 2 + 2/(x-1) - 3x/(x^2+4) + 1/(x^2 +4)
integrate this with respect to x to get
2x + 2 ln|x-1| - (3/2)ln (x^2 + 4) + (1/2) arctan (x/2) + C
Dr S S.
03/18/24
Wyzant T.
can you write out how you got A B C? I am not sure which numbers to plug in for x03/18/24