Raymond B. answered 03/14/24
Math, microeconomics or criminal justice
integral of (x^2+x+1)/(x+2)(x+1)^2 dx evaluated from 0 to 2
use partial fraction
= integral of (3/(x+2) - 2/(x+1) + 1/(x+1)^2) dx
= 3integral(dx/(x+2)dx -2integral(dx/(x+1) + integral(dx/(x+1)^2
use u substitution on each and plug back for x equivalents
=3ln|x+2| -2ln|x+1} - 1/(x+1) evaluated from 0 to 2
= 3ln2 -2ln3 + 2/3