Let us take a closer look at the denominator x2 - 2x + 1
Using the quadratic identity
(a - b)2 = a2 - 2ab + b2
we can write this denominator as
x2 - 2x + 1 = (x - 1)2
The highest term in the numerator is x4, of order 4.
The highest term in the denominator is x2, of order 2.
The highest term in the quotient will thus also be of order 2 (because x4 / x2 = x2)
Ax2 where A is a real number (the A here is actually 1 but since the instructions were to write the general form, we can keep it as A)
The next highest term in the quotient would be of order 1 (1 less than the previous term's order).
Bx where B is a real number
Note: it might turn out that B = 0 and that there is no term of order 1 in the quotient, which would be fine; we still need to account for it.
The next highest term in the quotient would be of order 0 (1 less than the previous term's order), so just a constant.
C where C is a real number
Note: it might turn out that C = 0 and that there is no term of order 0 in the quotient, which would be fine; we still need to account for it.
Finally, since the denominator can be written as (x - 1)2, we need two fractions for the remainder:
D / (x - 1) and
E / (x - 1)2
where D and E are real numbers
The general form of the partial fraction decomposition of the function
(x4 - 2x3 + x2 + 5x - 4) / (x2 - 2x + 1)
is thus given by
Ax2 + Bx + C + D / (x - 1) + E / (x - 1)2
where A, B, C, D, and E are real numbers.
Edit: due to the Homework system deeming this answer incorrect, here is an updated answer:
(x4 - 2x3 + x2 + 5x - 4) / (x2 - 2x + 1)
= (x4 - 2x3 + x2) / (x2 - 2x + 1) + (5x - 4) / (x2 - 2x + 1)
= x2(x2 - 2x + 1) / (x2 - 2x + 1) + (5x - 4) / (x2 - 2x + 1)
= x2 + (5x - 4) / (x2 - 2x + 1)
Since x2 - 2x + 1 = (x - 1)2
the last fraction can be decomposed into
A / (x - 1) + B / (x - 1)2
so that the general decomposition is
x2 + A / (x - 1) + B / (x - 1)2
where A and B are real numbers
Wyzant T.
My homework website says this is incorrect.03/14/24