Evelyn D.

asked • 03/10/24

Fractional part function math problem

I found this intriguing math problem online but can't get along with it.

I appreciate any help.


Prove that if "n" is a natural number, then there is no integer in this interval.

[\sqrt(16n+21); \sqrt(16n+24)]


Thank you.

1 Expert Answer

By:

Soumya M. answered • 03/10/24

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Evelyn D.

Thank you so much!
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03/11/24

Paul M.

tutor
Soumya M.: I agree that the difference between alpha and beta is less than 1 (although I think perhaps your algebra isn't quite right). alpha and beta are NOT integers; they are irrational numbers. It is not enough to show that they differ by no more than 1; 2 irrational numbers may differ by less than 1 yet the greatest integer in one may be one greater than the greatest integer in the other (e.g alpha=9.5, beta could be 10.2). And that is what I think needs to be proved, i.e. that the greatest integer in alpha equals the greatest integer in beta. As yet I do not know how to do that.
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03/11/24

Soumya M.

Paul M. I see what you’re saying. The condition I have proved is not strong enough. Btw I don’t see any problem with algebra. If my idea is correct I should have a right solution but it is too tedious to write it down. I’ll do it tomorrow.
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03/13/24

John C.

I agree with Soumya, the solution looks good! She'd only have to check 16n + 22 and 16n+23 also aren't squares (which she's basically already done with the mod 4 trick) since any integer squared in that range would have to be one of the 4 (16n+1 thru 16n+4). I also tried doing this problem, but with difference of squares and ran into trouble, so it's really nice to see a proof using modular arithmetic! Wasn't sure what background the poster assumed was necessary for the problem.
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03/16/24

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