Calculate the molarity of the hypochlorite ion OCL- provided.

Question

The mass of NaOCL added is 0.651 grams

the density given is 1.08g/ml

temperture 22C

6% W/V (weight/volume)

only 1mL of NaOCL as added to 5mL of EB solution (erythrosin B)

Answer 1

Step 1: Determine the mass of NaOCl in 1 mL of the NaOCl solution:

Given solution is 6% w/v, this means there are 6 grams of NaOCl in 100 mL of solution.

Therefore, in 1 mL of solution, the mass of NaOCl is:

Mass of NaOCl= 6g / 100 ml X 1ml = 0.06 g

Step 2: Calculate the number of moles of NaOCl in 1 mL of the solution:

The molar mass of NaOCl = 23 (Na) + 16 (O) + 35.5 (Cl)

= 0.000805mol

Step 3: Determine the total volume of the final solution:

The final solution has 1 mL of NaOCl added to 5 mL of erythrosin B,

so the total volume is: 1ml + 5ml = 6ml

Step 4: Convert the total volume to liters

6ml = 6×10⁻³ l

Step 5: Calculate the molarity of the hypochlorite ion (OCl¯) in the final solution:

Molarity (M) is given by the number of moles of solute divided by the volume of solution in liters:

M = mass of solute

volume of solution in liters

M = 0.000805 mol​

6×10⁻³ l

= 0.134 M

the molarity of the hypochlorite ion (OCl¯) in the final solution is 0.134 M