find the 9th term of the geometric sequence whose common ratio is 3/2 and whose first term is 5

Answer 1

The general form of a geometric sequence can be written as a_n = a₁•r^n-1 where "n" is 9, "r" is the common ratio and "a¹" is 5

a₉ = 5•(3/2)⁸

Plug in a calculator to get a₉ = 32805/256 or approx 128.1445