Raymond B. answered 03/14/24
Math, microeconomics or criminal justice
A=Pe^rt with r=annual rate of interest= 10%, t = 8 years, A=120000 e=about 2.718281828...
120000=Pe^(8(1/10) P= amount needed to investment at time t=0
120000/P = e^.8
ln(120000/P) =.8
ln2.23 = about .8
120,000/P = about 2.23
P = about 120000/2.23 = about $53,800
if interest is compounded continuously or approximately daily on a 53800 investment at 10% for 8 years
reaching $120,000
if compounded annually
A=P(1+r/n)^nt with n=1, r=.10, t=8, A=120000
120000=P(1.1^8)
P = 120000/1.1^8 = about $55,981 investment
for compounding between annually and continuously, such as quarterly or monthly
53800<P<55981 for 10% interest to reach 120000 in 8 years