Raymond B. answered 03/26/24
Math, microeconomics or criminal justice
300 grams 550 years ago when t=0
half life = 200 years
150 grams 350 years ago when t=200
75 grams 150 years ago when t=400
37.5 grams 50 years from now when t=600
find grams now when t=550
and when will grams decay to 40 grams
A=Pe^rt
A/P =150/300 = 1/2 = e^200r
200r = ln.5
r = (ln.5)/200
A=300e^(ln.5)/200)(550) = Amount now
= 300e^(11/4)ln.5)= 300e^(2.75)(ln.5)
= about 44.60 grams now
40 = 300e^(t/200)(ln.5), solve for t, to find when grams =40
ln(2/15) = (t/200)ln.5
t = 200ln(2/15)/ln.5
= about 581.38 = 31.38 years from now
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