William W. answered 03/01/24
Top Pre-Calc Tutor
Step 1: Get rid of sin(2t) by using the trig identity sin(2x) = 2sin(x)cos(x):
0∫πecos(t)sin(2t) dt = 0∫πecos(t)(2sin(t)cos(t)) dt
then move the constant out front:
20∫πecos(t)(sin(t)cos(t)) dt then rearrange the sine and cosine to get:
20∫πecos(t)cos(t) sin(t)dt
Step 2, let w = cos(t) which makes dw = -sin(t) dt or (-1)dw = sin(t) dt
then substitute to turn the integral into:
20∫πew•w•(-1)dw
then move the "-1" constant out front:
-20∫πew•w dw
Step 3, Use Integration by Parts
Rule: ∫u dv = uv - ∫v du
Let u = w which makes du = dw
Let dv = ew which makes v = ew
So ∫ew•w dw = w•ew - ∫ew dw
Realizing that the anti-derivative of ew is ew we get:
∫ew•w dw = w•ew - ew
So -20∫πew•w dw = -2(w•ew - ew) evaluated for zero to π
Converting back to cos(t), because w = cos(t) we get:
-2(cos(t)•ecos(t) - ecos(t)) evaluated for zero to π or, simplifying:
-2ecos(t)(cos(t) - 1)
Plug in t = π and t = 0 to get:
For t = π:
-2ecos(π)(cos(π) - 1)
-2e-1(-1 - 1)
4/e
For t = 0
-2ecos(0)(cos(0) - 1)
-2e1(1 - 1)
0
So, putting those together, the integral equals 4/e - 0 or 4/e