
Dayv O. answered 02/28/24
Caring Super Enthusiastic Knowledgeable Pre-Calculus Tutor
Assuming base areas are same for both tanks
can write
hA(t)=h0A(1-mAt) ,,,,mA is pump rate for tank A
hB(t)=10(1-mBt) ,,,mB is pump rate for tank B
t=5 ,,hA=0
mA=1/5
t=8 ,,,hB=0
mB=1/8
at t=2 hA=hB
h0A(3/5)=10(3/4)
h0A=50/4 meters