Find the equation of the line passing through the points -11 -5 and -33 -9, right in the form of Y equals MX plus B

Question

(-11,-5) and (-33,-9)

Answer 1

Since you are given two points, start with two-point form of the equation.

(y + 11) / (x + 5) = (-33 + 11) / (-9 + 5)

Can you simplify and convert to requested form?

Answer 2

Start by finding the slope.

slope = change in y's (rise)/change in x's(run)

m = (y2 - y1) / (x2 - x1)

Enter in using the given points

m = (-9 - -5) / (-33 - -11)

Rewrite as needed

m = (-9 + 5) / (-33 + 11)

Simplify

m = (-4) / (-22)

Simplify the fraction

m = 2/11

Now you can use either the slope-intercept or point-slope formulas to complete the equation.

Slope Intercept [y = mx + b]

1) Use the slope above and either of the original points to find the y-intercept (b).

-5 = 2/11(-11) + b

Multiply 2/11 by -11

-5 = -2 + b

Add 2 to each side

-3 = b

2) Now plug in the slope, m, and y-intercept, b, into slope intercept form to complete your equation.

y = 2/11x - 3

Point-Slope [(y - y1) = m(x - x1)]

Use the slope above and either of the original points to write your equation.

y - -5 = 2/11(x - -11)

Update the signs - subtracting a negative becomes adding a positive

y + 5 = 2/11(x + 11)

Distribute the 2/11 to each term on the group.

y + 5 = 2/11x + 2

Subtract 5 from each side to complete the equation.

y = 2/11x - 3

Answer 3

m = (-9 - (-5)) / (-33 - (-11)) = -4 / (-22) = 2/11

y = (2/11)x + b

Since (-11, -5) is on the graph, -5 = (2/11)(-11) + b. So, b = -3.

y = (2/11)x - 3