
Aime F. answered 02/19/24
Experienced University Professor of Mathematics & Data Science
Let B = [a b c; b d e; c e f] which has 6 unknowns. Then AB = [a–b, b–d, c–e; b+c, d+e, e+f; a–c, b–e, c–f], and BA⸆ = [...] so AB = BA⸆ provides 9 equations, some of which will be redundant. These are enough to solve for some of a, b, c, d, e, f in terms of others. That is, B will not be unique.