Use the​ slope-intercept form to graph the equation

Question

y= - 7/5 x +5

Answer 1

With a linear function in this form y=ax+b --> its slope is a and y-intercept is the point (0,b). We can always begin with the y-intercept, and then use the slope to find another point. Because two points always determine a unique line, we simply connect them and we are done!

For your equation, y = -7/5x + 5, we can see that the y-intercept is (0,5) and the slope is -7/5, which remember means we travel down 7 and right 5 since slope is rise over run. If you plot (0,5), and then travel down 7 and right 5, we arrive at the point (5,-2) which must be another point on the line! (Plug in 5 for x and -2 for y to check, if you like)

Now we know two points on this straight line! They are (0,5) and (5,-2). Connect them with a ruler and you've got it!

Answer 2

Hi Trinity,

I cannot post graphs here due to character limits, but just plot points. First, set x=0. At x=0, y=5, so your first point is (0,5). That's also your y-intercept. Then move up to 1. At x=1, y = -7/5 +5= 18/5. So plot (1, 18/5). Then set x= -1. At x=-1, y = (-7/5)(-1) +5 = 32/5, so plot (-1, 32/5). The linear form should be apparent once you plot these three points. I hope this helps.