Raymond B. answered 02/10/24
Math, microeconomics or criminal justice
-4,-2,5 zeros
x=-4, x+4=0
x=-2, x+2=0
x=5, x-5=0
have factors (x+4)(x+2)(x-5)
f(x) = (x^2+6x+8)(x-5)
= x^3 +x^2 -22x -40
x=4, x-4=0
x=6-sqr7, x-6=-sqr7, x^2-12x+36 = 7
have factors (x-4)(x^2-12x+29)
f(x)=x^3 -16x^2 +77x -116
x=0, x=5, x=-5+sqr8
have factors x, x-5 and x^2 -10x+17
f(x) = x(x-5)(x^2-10x+17)
= x(x^3-15x^2+67x -86)
= x^4 -15x^3+57x^2-86x