Mark M. answered 02/06/24
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
g(x) = x5 - x4
g'(x) = 5x4 - 4x3
g"(x) = 20x3 - 12x2 = 4x2(5x - 3) = 0 when x = 0 or 3/5
When x < 0, g"(x) < 0. So, g'(x) is decreasing.
When 0 < x < 3/5, g"(x) < 0. So, g'(x) is decreasing.
When x > 3/5, g"(x) > 0. So, g'(x) is increasing.
g'(x) is minimized when x = 3/5.