Suppose that there are two types of tickets to a show.

Question

Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $35 and same-day tickets cost $40. For one performance, there were 70 tickets sold in all, and the total amount paid for them was $2650. How many tickets of each type were sold?

Number of advanced Tickets Sold:

Number of same day tickets sold:

Answer 1

Advanced Tickets = $35

Same Day = $40

70 = total tickets

x = number of advance day tickets sold

so (70-x) = same day tickets

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$2650 = $35(x) + $40(70-x)

2650 = 35x + 2800 - 40x

-2800+2650 = -5x

-150=--5x

x = 30; the number of advanced tickets

Therefore 70-30 = 40 day of ticktes

Check the answer:

2650 = 35*30 + 40*40

2650=1050+1600

2650=2650