A pool measuring 20 m x 24 m is surrounded by a path of uniform width as shown in the figure if the area of the pool and the path combined is 1152 square meters what is the width of the path?

Answer 1

Let x = width of the path

(20 + 2x)(24 + 2x) = 1152

4x² + 88x + 480 = 1152

4x² + 88x - 672 = 0

x² + 22x - 168 = 0

(x - 6)(x + 28) = 0

x = 6 ft