Raymond B. answered 01/30/24
Math, microeconomics or criminal justice
unemployment rate = 4.4% = .044
a random sample of 20 is taken
what is the probability exactly 3 are unemployed?
exactly 0 unemployed would be probability = P(0) = 20C0(.956^20)(.044^0) = (.956^20)
exactly 1 unemployed: P(1) = 20C1(.956^19).044^1
exactly 2 unemployed P(2) = 20C2(.956^18)(.044^2)
exactly 3 unemployed: P(3)= 20C3(.956^17)(.044^3) = 20!/17!3!(.956^17)(.044^3) = (20)(19)(18)/(3)(2)(.956^17)(.044^3)
=1140(.956^17)(.044^3)
=about .04519049 = .0452 for 4 decimal places
= about 4.519049% = 4.519% for 4 decimal places
=chance of exactly 3 unemployed in a sample of 20 with 4.4% unemployment rate
= about .45% probability= slightly less than 1/2 %