Raymond B. answered 01/29/24
Math, microeconomics or criminal justice
1/25650 = the probability a pear is golden = 3.89863548 x 10^-5
=3,89863548 x 10^-3 percent
try a simpler problem with 60 fruit
1/2 are pears and 1/3 of all are golden
what are the odds of a random pear being golden
Pr(g/p) = 1/3
60 fruit, 30 pears, 20 of all are golden
of those 20 golden fruit half are pears. 10/30= 1/3
so instead of 1/3, you have 1/25650
and instead of 1/2 you have 5%=.05 = 1/20
Pr(g/p) = probability of golden given a pear = 1/25650
the 1/2 and the 5% were surplusage, extraneous information
UNLESS the problem really intended to ask what is the probability
of a randomly selected fruit being a golden pear
then Probability = 1/25650 x .05 = 1/51300= 1.949317739 x 10^-6
unless it was a trick question, they wouldn't have mentioned the 5%
so it seems like they probably were asking what is the chance of a golden pear if you randomly select a fruit
even then that barrel with 100 fruit is irrelevant to the problem, if interpreted either way above
it seems like it's partly a trick question, trying to get you to use irrelevant numbers in the calculation