Inactive Tutor answered 01/27/24
she saves 900 in january, and 1200 in february
her donation increases by 35 from january to february
her donation is directly proportional to the square of her savings
d = ks^2
d = k900^2 = 810000k
''for january
d = k1200^2 = 1440000k
for february
1440000k = 35 + 810000k
1440000k- 810000k = 35
630000k = 35
k = 35/630000 = 7/126000
in january d=(7/126000)900^2
= (7/126)810
= $45
in february d= (7/126000)1200^2
= $80
80-45=35
5 men are hired, by hiring a 6th man the job can be completed 8 days earlier
how many more men should be hired to complete the job 28 days earlier?
let x = the number of days it takes 5 men to complete the job
then x-8 = days for 6 men to complete the job
x-28 = days for y men to complete the job
each man works at the same rate
it takes 1 man alone to complete the job in 5x days
it takes 5 men to complete the job in 5x/5 = x days
it take 6 men to complete the job in x-8 days
z days for 1 man to complete the job
5 men do the job in z/5 days
6 men do the job in z/6 days
z/6 = z/5 -8
5z =6z -240
z = 240 days for 1 man to complete the job
5 men do the job in 240/5 = 48 days
6 men do the job in 240/6 = 40 days
to do the job in 48-28= 20 days
requires 240/y = 20
20y=240
y = 12 men
you need 12 men to do the job in 28 days less
so if you have 6, you need 6 more men