Raymond B. answered 01/27/24
Math, microeconomics or criminal justice
she saves 900 in january, and 1200 in february
her donation increases by 35 from january to february
her donation is directly proportional to the square of her savings
d = ks^2
d = k900^2 = 810000k
''for january
d = k1200^2 = 1440000k
for february
1440000k = 35 + 810000k
1440000k- 810000k = 35
630000k = 35
k = 35/630000 = 7/126000
in january d=(7/126000)900^2
= (7/126)810
= $45
in february d= (7/126000)1200^2
= $80
80-45=35
5 men are hired, by hiring a 6th man the job can be completed 8 days earlier
how many more men should be hired to complete the job 28 days earlier?
let x = the number of days it takes 5 men to complete the job
then x-8 = days for 6 men to complete the job
x-28 = days for y men to complete the job
each man works at the same rate
it takes 1 man alone to complete the job in 5x days
it takes 5 men to complete the job in 5x/5 = x days
it take 6 men to complete the job in x-8 days
z days for 1 man to complete the job
5 men do the job in z/5 days
6 men do the job in z/6 days
z/6 = z/5 -8
5z =6z -240
z = 240 days for 1 man to complete the job
5 men do the job in 240/5 = 48 days
6 men do the job in 240/6 = 40 days
to do the job in 48-28= 20 days
requires 240/y = 20
20y=240
y = 12 men
you need 12 men to do the job in 28 days less
so if you have 6, you need 6 more men