write the equation of the line in slope-intercept form that is perpendicular to the graph of y+4=-2/3(x-2) and goes through the point (-8,3)

Answer 1

y+4=-2/3(x-2)

y + 4 = -2x/3 +4/3

The slope is -2/3.

The slope of a line perpendicular to that will be 3/2.

Slope Intercept Form is y = mx + b

The m is the slope, and b is the y-intercept.

Find B by plugging in the given point (-8.3)

3 = (3/2)*(-8) + b

3 = -12 + b

12+3 = 15 = b

y = (3/2)x + 15

Answer 2

y - 3 = (3/2)(x + 8)