write the equation of the line in slope-intercept form that is parallel to the graph of 2x-3y=5 and goes through the point (-3,4)

Answer 1

2x-3y = 5

3y = 2x-5

y = 2x/3 -5/3, has slope = 2/3. all parallel lines have the same 2/3 slope

y=2x/3 +b, to solve for b plug in the point (-3,4)

4 = 2(-3)/3 +b

4 = -2 +b

b = 4+2 =6

y = (2/3)x +6 is the equation of the parallel line through the given point