Find the x-intercept of the line 8x+6y=16. Write your answer as an integer or as a simplified proper or improper fraction, not as an ordered pair.

Answer 1

Hi Iris,

Your question is:

Find the x-intercept of the line 8x+6y=16. Write your answer as an integer or as a simplified proper or improper fraction, not as an ordered pair.

Given: Line 8x + 6y = 16

Find: x-intercept written as an integer not ordered pair.

First, the definition of x-intercept is where the line crosses the x-axis. This happens when your "y" value is equal to 0. (Any point that crosses the x-axis has coordinates of (x-intercept, 0)

So one way to find the x-intercept, is to place 0 in for y and solve for x.

8x + 6y = 16

8x + 6(0) = 16

8x = 16

x = 2

So your x-intercept is 2

Hope this helps!!

Answer 2

X-intercepts are the x-values of a point (or points!) on the line described by the equation where "0" is the y-value. If we substitute "0" for "y", and then solve for x, our result will be the x-intercept of the equation.

WORK:

A. Write the equation:

8x + 6y = 16

B. Replace "y" with "0"

8x + 6(0) = 16

C. Simplify the equation

8x = 16

D. Simplify by dividing BOTH SIDES of the equation by the coefficient of x, which is 8.

8x/8 = 16/8

x = 2

REMEMBER: The numbers to the left of the variables are called "coefficients", and they are being multiplied by the variable. When we substitute a "number" for a "variable", we still have to multiply that number by it's coefficient.