The usual way to do this is to find the critical points: the ones where the derivative f'(x) = 0.
f'(x) = -20x^3+9x^2+4x+1, so if you want to you can check whether there are any zeros between 1 and -1 with your calculator. You can find the largest and smallest values of f at these, and compare to f(1) and f(-1) to find the global extrema.
Since this is multiple choice though, it might be faster to "cheat" and plug in the values given in B,C, D to see which is the global max and which is the global min.